\(\int \frac {x^4 (a+b x^2)}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx\) [358]
Optimal result
Integrand size = 31, antiderivative size = 164 \[
\int \frac {x^4 \left (a+b x^2\right )}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx=\frac {c^2 \left (5 b c^2+6 a d^2\right ) x \sqrt {-c+d x} \sqrt {c+d x}}{16 d^6}+\frac {\left (5 b c^2+6 a d^2\right ) x^3 \sqrt {-c+d x} \sqrt {c+d x}}{24 d^4}+\frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}+\frac {c^4 \left (5 b c^2+6 a d^2\right ) \text {arctanh}\left (\frac {\sqrt {-c+d x}}{\sqrt {c+d x}}\right )}{8 d^7}
\]
[Out]
1/8*c^4*(6*a*d^2+5*b*c^2)*arctanh((d*x-c)^(1/2)/(d*x+c)^(1/2))/d^7+1/16*c^2*(6*a*d^2+5*b*c^2)*x*(d*x-c)^(1/2)*
(d*x+c)^(1/2)/d^6+1/24*(6*a*d^2+5*b*c^2)*x^3*(d*x-c)^(1/2)*(d*x+c)^(1/2)/d^4+1/6*b*x^5*(d*x-c)^(1/2)*(d*x+c)^(
1/2)/d^2
Rubi [A] (verified)
Time = 0.08 (sec) , antiderivative size = 164, normalized size of antiderivative = 1.00, number of
steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.226, Rules used = {471, 102, 12, 92, 65, 223, 212}
\[
\int \frac {x^4 \left (a+b x^2\right )}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx=\frac {c^4 \left (6 a d^2+5 b c^2\right ) \text {arctanh}\left (\frac {\sqrt {d x-c}}{\sqrt {c+d x}}\right )}{8 d^7}+\frac {c^2 x \sqrt {d x-c} \sqrt {c+d x} \left (6 a d^2+5 b c^2\right )}{16 d^6}+\frac {x^3 \sqrt {d x-c} \sqrt {c+d x} \left (6 a d^2+5 b c^2\right )}{24 d^4}+\frac {b x^5 \sqrt {d x-c} \sqrt {c+d x}}{6 d^2}
\]
[In]
Int[(x^4*(a + b*x^2))/(Sqrt[-c + d*x]*Sqrt[c + d*x]),x]
[Out]
(c^2*(5*b*c^2 + 6*a*d^2)*x*Sqrt[-c + d*x]*Sqrt[c + d*x])/(16*d^6) + ((5*b*c^2 + 6*a*d^2)*x^3*Sqrt[-c + d*x]*Sq
rt[c + d*x])/(24*d^4) + (b*x^5*Sqrt[-c + d*x]*Sqrt[c + d*x])/(6*d^2) + (c^4*(5*b*c^2 + 6*a*d^2)*ArcTanh[Sqrt[-
c + d*x]/Sqrt[c + d*x]])/(8*d^7)
Rule 12
Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] && !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]
Rule 65
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]
Rule 92
Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[b*(a + b*x
)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d*f*(n + p + 3))), x] + Dist[1/(d*f*(n + p + 3)), Int[(c + d*x)^n*(e +
f*x)^p*Simp[a^2*d*f*(n + p + 3) - b*(b*c*e + a*(d*e*(n + 1) + c*f*(p + 1))) + b*(a*d*f*(n + p + 4) - b*(d*e*(
n + 2) + c*f*(p + 2)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 3, 0]
Rule 102
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[b*(a +
b*x)^(m - 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d*f*(m + n + p + 1))), x] + Dist[1/(d*f*(m + n + p + 1)), I
nt[(a + b*x)^(m - 2)*(c + d*x)^n*(e + f*x)^p*Simp[a^2*d*f*(m + n + p + 1) - b*(b*c*e*(m - 1) + a*(d*e*(n + 1)
+ c*f*(p + 1))) + b*(a*d*f*(2*m + n + p) - b*(d*e*(m + n) + c*f*(m + p)))*x, x], x], x] /; FreeQ[{a, b, c, d,
e, f, n, p}, x] && GtQ[m, 1] && NeQ[m + n + p + 1, 0] && IntegerQ[m]
Rule 212
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])
Rule 223
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] && !GtQ[a, 0]
Rule 471
Int[((e_.)*(x_))^(m_.)*((a1_) + (b1_.)*(x_)^(non2_.))^(p_.)*((a2_) + (b2_.)*(x_)^(non2_.))^(p_.)*((c_) + (d_.)
*(x_)^(n_)), x_Symbol] :> Simp[d*(e*x)^(m + 1)*(a1 + b1*x^(n/2))^(p + 1)*((a2 + b2*x^(n/2))^(p + 1)/(b1*b2*e*(
m + n*(p + 1) + 1))), x] - Dist[(a1*a2*d*(m + 1) - b1*b2*c*(m + n*(p + 1) + 1))/(b1*b2*(m + n*(p + 1) + 1)), I
nt[(e*x)^m*(a1 + b1*x^(n/2))^p*(a2 + b2*x^(n/2))^p, x], x] /; FreeQ[{a1, b1, a2, b2, c, d, e, m, n, p}, x] &&
EqQ[non2, n/2] && EqQ[a2*b1 + a1*b2, 0] && NeQ[m + n*(p + 1) + 1, 0]
Rubi steps \begin{align*}
\text {integral}& = \frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}-\frac {1}{6} \left (-6 a-\frac {5 b c^2}{d^2}\right ) \int \frac {x^4}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx \\ & = \frac {\left (5 b c^2+6 a d^2\right ) x^3 \sqrt {-c+d x} \sqrt {c+d x}}{24 d^4}+\frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}+\frac {\left (5 b c^2+6 a d^2\right ) \int \frac {3 c^2 x^2}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx}{24 d^4} \\ & = \frac {\left (5 b c^2+6 a d^2\right ) x^3 \sqrt {-c+d x} \sqrt {c+d x}}{24 d^4}+\frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}+\frac {\left (c^2 \left (5 b c^2+6 a d^2\right )\right ) \int \frac {x^2}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx}{8 d^4} \\ & = \frac {c^2 \left (5 b c^2+6 a d^2\right ) x \sqrt {-c+d x} \sqrt {c+d x}}{16 d^6}+\frac {\left (5 b c^2+6 a d^2\right ) x^3 \sqrt {-c+d x} \sqrt {c+d x}}{24 d^4}+\frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}+\frac {\left (c^2 \left (5 b c^2+6 a d^2\right )\right ) \int \frac {c^2}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx}{16 d^6} \\ & = \frac {c^2 \left (5 b c^2+6 a d^2\right ) x \sqrt {-c+d x} \sqrt {c+d x}}{16 d^6}+\frac {\left (5 b c^2+6 a d^2\right ) x^3 \sqrt {-c+d x} \sqrt {c+d x}}{24 d^4}+\frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}+\frac {\left (c^4 \left (5 b c^2+6 a d^2\right )\right ) \int \frac {1}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx}{16 d^6} \\ & = \frac {c^2 \left (5 b c^2+6 a d^2\right ) x \sqrt {-c+d x} \sqrt {c+d x}}{16 d^6}+\frac {\left (5 b c^2+6 a d^2\right ) x^3 \sqrt {-c+d x} \sqrt {c+d x}}{24 d^4}+\frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}+\frac {\left (c^4 \left (5 b c^2+6 a d^2\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {2 c+x^2}} \, dx,x,\sqrt {-c+d x}\right )}{8 d^7} \\ & = \frac {c^2 \left (5 b c^2+6 a d^2\right ) x \sqrt {-c+d x} \sqrt {c+d x}}{16 d^6}+\frac {\left (5 b c^2+6 a d^2\right ) x^3 \sqrt {-c+d x} \sqrt {c+d x}}{24 d^4}+\frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}+\frac {\left (c^4 \left (5 b c^2+6 a d^2\right )\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\sqrt {-c+d x}}{\sqrt {c+d x}}\right )}{8 d^7} \\ & = \frac {c^2 \left (5 b c^2+6 a d^2\right ) x \sqrt {-c+d x} \sqrt {c+d x}}{16 d^6}+\frac {\left (5 b c^2+6 a d^2\right ) x^3 \sqrt {-c+d x} \sqrt {c+d x}}{24 d^4}+\frac {b x^5 \sqrt {-c+d x} \sqrt {c+d x}}{6 d^2}+\frac {c^4 \left (5 b c^2+6 a d^2\right ) \tanh ^{-1}\left (\frac {\sqrt {-c+d x}}{\sqrt {c+d x}}\right )}{8 d^7} \\
\end{align*}
Mathematica [A] (verified)
Time = 0.38 (sec) , antiderivative size = 119, normalized size of antiderivative = 0.73
\[
\int \frac {x^4 \left (a+b x^2\right )}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx=\frac {d x \sqrt {-c+d x} \sqrt {c+d x} \left (6 a d^2 \left (3 c^2+2 d^2 x^2\right )+b \left (15 c^4+10 c^2 d^2 x^2+8 d^4 x^4\right )\right )+6 c^4 \left (5 b c^2+6 a d^2\right ) \text {arctanh}\left (\frac {\sqrt {-c+d x}}{\sqrt {c+d x}}\right )}{48 d^7}
\]
[In]
Integrate[(x^4*(a + b*x^2))/(Sqrt[-c + d*x]*Sqrt[c + d*x]),x]
[Out]
(d*x*Sqrt[-c + d*x]*Sqrt[c + d*x]*(6*a*d^2*(3*c^2 + 2*d^2*x^2) + b*(15*c^4 + 10*c^2*d^2*x^2 + 8*d^4*x^4)) + 6*
c^4*(5*b*c^2 + 6*a*d^2)*ArcTanh[Sqrt[-c + d*x]/Sqrt[c + d*x]])/(48*d^7)
Maple [A] (verified)
Time = 4.08 (sec) , antiderivative size = 160, normalized size of antiderivative = 0.98
| | |
method | result | size |
| | |
risch |
\(-\frac {x \left (8 b \,d^{4} x^{4}+12 a \,d^{4} x^{2}+10 b \,c^{2} d^{2} x^{2}+18 a \,c^{2} d^{2}+15 b \,c^{4}\right ) \left (-d x +c \right ) \sqrt {d x +c}}{48 d^{6} \sqrt {d x -c}}+\frac {c^{4} \left (6 a \,d^{2}+5 b \,c^{2}\right ) \ln \left (\frac {x \,d^{2}}{\sqrt {d^{2}}}+\sqrt {d^{2} x^{2}-c^{2}}\right ) \sqrt {\left (d x -c \right ) \left (d x +c \right )}}{16 d^{6} \sqrt {d^{2}}\, \sqrt {d x -c}\, \sqrt {d x +c}}\) |
\(160\) |
default |
\(\frac {\sqrt {d x -c}\, \sqrt {d x +c}\, \left (8 \,\operatorname {csgn}\left (d \right ) b \,d^{5} x^{5} \sqrt {d^{2} x^{2}-c^{2}}+12 \,\operatorname {csgn}\left (d \right ) a \,d^{5} x^{3} \sqrt {d^{2} x^{2}-c^{2}}+10 \,\operatorname {csgn}\left (d \right ) b \,c^{2} d^{3} x^{3} \sqrt {d^{2} x^{2}-c^{2}}+18 \,\operatorname {csgn}\left (d \right ) d^{3} \sqrt {d^{2} x^{2}-c^{2}}\, a \,c^{2} x +15 \,\operatorname {csgn}\left (d \right ) d \sqrt {d^{2} x^{2}-c^{2}}\, b \,c^{4} x +18 \ln \left (\left (\sqrt {d^{2} x^{2}-c^{2}}\, \operatorname {csgn}\left (d \right )+d x \right ) \operatorname {csgn}\left (d \right )\right ) a \,c^{4} d^{2}+15 \ln \left (\left (\sqrt {d^{2} x^{2}-c^{2}}\, \operatorname {csgn}\left (d \right )+d x \right ) \operatorname {csgn}\left (d \right )\right ) b \,c^{6}\right ) \operatorname {csgn}\left (d \right )}{48 d^{7} \sqrt {d^{2} x^{2}-c^{2}}}\) |
\(240\) |
| | |
|
|
|
[In]
int(x^4*(b*x^2+a)/(d*x-c)^(1/2)/(d*x+c)^(1/2),x,method=_RETURNVERBOSE)
[Out]
-1/48*x*(8*b*d^4*x^4+12*a*d^4*x^2+10*b*c^2*d^2*x^2+18*a*c^2*d^2+15*b*c^4)*(-d*x+c)*(d*x+c)^(1/2)/d^6/(d*x-c)^(
1/2)+1/16*c^4*(6*a*d^2+5*b*c^2)/d^6*ln(x*d^2/(d^2)^(1/2)+(d^2*x^2-c^2)^(1/2))/(d^2)^(1/2)*((d*x-c)*(d*x+c))^(1
/2)/(d*x-c)^(1/2)/(d*x+c)^(1/2)
Fricas [A] (verification not implemented)
none
Time = 0.27 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.70
\[
\int \frac {x^4 \left (a+b x^2\right )}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx=\frac {{\left (8 \, b d^{5} x^{5} + 2 \, {\left (5 \, b c^{2} d^{3} + 6 \, a d^{5}\right )} x^{3} + 3 \, {\left (5 \, b c^{4} d + 6 \, a c^{2} d^{3}\right )} x\right )} \sqrt {d x + c} \sqrt {d x - c} - 3 \, {\left (5 \, b c^{6} + 6 \, a c^{4} d^{2}\right )} \log \left (-d x + \sqrt {d x + c} \sqrt {d x - c}\right )}{48 \, d^{7}}
\]
[In]
integrate(x^4*(b*x^2+a)/(d*x-c)^(1/2)/(d*x+c)^(1/2),x, algorithm="fricas")
[Out]
1/48*((8*b*d^5*x^5 + 2*(5*b*c^2*d^3 + 6*a*d^5)*x^3 + 3*(5*b*c^4*d + 6*a*c^2*d^3)*x)*sqrt(d*x + c)*sqrt(d*x - c
) - 3*(5*b*c^6 + 6*a*c^4*d^2)*log(-d*x + sqrt(d*x + c)*sqrt(d*x - c)))/d^7
Sympy [F(-1)]
Timed out. \[
\int \frac {x^4 \left (a+b x^2\right )}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx=\text {Timed out}
\]
[In]
integrate(x**4*(b*x**2+a)/(d*x-c)**(1/2)/(d*x+c)**(1/2),x)
[Out]
Timed out
Maxima [A] (verification not implemented)
none
Time = 0.27 (sec) , antiderivative size = 196, normalized size of antiderivative = 1.20
\[
\int \frac {x^4 \left (a+b x^2\right )}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx=\frac {\sqrt {d^{2} x^{2} - c^{2}} b x^{5}}{6 \, d^{2}} + \frac {5 \, \sqrt {d^{2} x^{2} - c^{2}} b c^{2} x^{3}}{24 \, d^{4}} + \frac {\sqrt {d^{2} x^{2} - c^{2}} a x^{3}}{4 \, d^{2}} + \frac {5 \, b c^{6} \log \left (2 \, d^{2} x + 2 \, \sqrt {d^{2} x^{2} - c^{2}} d\right )}{16 \, d^{7}} + \frac {3 \, a c^{4} \log \left (2 \, d^{2} x + 2 \, \sqrt {d^{2} x^{2} - c^{2}} d\right )}{8 \, d^{5}} + \frac {5 \, \sqrt {d^{2} x^{2} - c^{2}} b c^{4} x}{16 \, d^{6}} + \frac {3 \, \sqrt {d^{2} x^{2} - c^{2}} a c^{2} x}{8 \, d^{4}}
\]
[In]
integrate(x^4*(b*x^2+a)/(d*x-c)^(1/2)/(d*x+c)^(1/2),x, algorithm="maxima")
[Out]
1/6*sqrt(d^2*x^2 - c^2)*b*x^5/d^2 + 5/24*sqrt(d^2*x^2 - c^2)*b*c^2*x^3/d^4 + 1/4*sqrt(d^2*x^2 - c^2)*a*x^3/d^2
+ 5/16*b*c^6*log(2*d^2*x + 2*sqrt(d^2*x^2 - c^2)*d)/d^7 + 3/8*a*c^4*log(2*d^2*x + 2*sqrt(d^2*x^2 - c^2)*d)/d^
5 + 5/16*sqrt(d^2*x^2 - c^2)*b*c^4*x/d^6 + 3/8*sqrt(d^2*x^2 - c^2)*a*c^2*x/d^4
Giac [A] (verification not implemented)
none
Time = 0.31 (sec) , antiderivative size = 203, normalized size of antiderivative = 1.24
\[
\int \frac {x^4 \left (a+b x^2\right )}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx=\frac {{\left ({\left (2 \, {\left ({\left (d x + c\right )} {\left (4 \, {\left (d x + c\right )} {\left (\frac {{\left (d x + c\right )} b}{d^{6}} - \frac {5 \, b c}{d^{6}}\right )} + \frac {3 \, {\left (15 \, b c^{2} d^{36} + 2 \, a d^{38}\right )}}{d^{42}}\right )} - \frac {55 \, b c^{3} d^{36} + 18 \, a c d^{38}}{d^{42}}\right )} {\left (d x + c\right )} + \frac {85 \, b c^{4} d^{36} + 54 \, a c^{2} d^{38}}{d^{42}}\right )} {\left (d x + c\right )} - \frac {3 \, {\left (11 \, b c^{5} d^{36} + 10 \, a c^{3} d^{38}\right )}}{d^{42}}\right )} \sqrt {d x + c} \sqrt {d x - c} - \frac {6 \, {\left (5 \, b c^{6} + 6 \, a c^{4} d^{2}\right )} \log \left ({\left | -\sqrt {d x + c} + \sqrt {d x - c} \right |}\right )}{d^{6}}}{48 \, d}
\]
[In]
integrate(x^4*(b*x^2+a)/(d*x-c)^(1/2)/(d*x+c)^(1/2),x, algorithm="giac")
[Out]
1/48*(((2*((d*x + c)*(4*(d*x + c)*((d*x + c)*b/d^6 - 5*b*c/d^6) + 3*(15*b*c^2*d^36 + 2*a*d^38)/d^42) - (55*b*c
^3*d^36 + 18*a*c*d^38)/d^42)*(d*x + c) + (85*b*c^4*d^36 + 54*a*c^2*d^38)/d^42)*(d*x + c) - 3*(11*b*c^5*d^36 +
10*a*c^3*d^38)/d^42)*sqrt(d*x + c)*sqrt(d*x - c) - 6*(5*b*c^6 + 6*a*c^4*d^2)*log(abs(-sqrt(d*x + c) + sqrt(d*x
- c)))/d^6)/d
Mupad [B] (verification not implemented)
Time = 58.97 (sec) , antiderivative size = 1682, normalized size of antiderivative = 10.26
\[
\int \frac {x^4 \left (a+b x^2\right )}{\sqrt {-c+d x} \sqrt {c+d x}} \, dx=\text {Too large to display}
\]
[In]
int((x^4*(a + b*x^2))/((c + d*x)^(1/2)*(d*x - c)^(1/2)),x)
[Out]
((5*b*c^6*((c + d*x)^(1/2) - c^(1/2)))/(4*((-c)^(1/2) - (d*x - c)^(1/2))) - (175*b*c^6*((c + d*x)^(1/2) - c^(1
/2))^3)/(12*((-c)^(1/2) - (d*x - c)^(1/2))^3) + (311*b*c^6*((c + d*x)^(1/2) - c^(1/2))^5)/(4*((-c)^(1/2) - (d*
x - c)^(1/2))^5) + (8361*b*c^6*((c + d*x)^(1/2) - c^(1/2))^7)/(4*((-c)^(1/2) - (d*x - c)^(1/2))^7) + (42259*b*
c^6*((c + d*x)^(1/2) - c^(1/2))^9)/(6*((-c)^(1/2) - (d*x - c)^(1/2))^9) + (25295*b*c^6*((c + d*x)^(1/2) - c^(1
/2))^11)/(2*((-c)^(1/2) - (d*x - c)^(1/2))^11) + (25295*b*c^6*((c + d*x)^(1/2) - c^(1/2))^13)/(2*((-c)^(1/2) -
(d*x - c)^(1/2))^13) + (42259*b*c^6*((c + d*x)^(1/2) - c^(1/2))^15)/(6*((-c)^(1/2) - (d*x - c)^(1/2))^15) + (
8361*b*c^6*((c + d*x)^(1/2) - c^(1/2))^17)/(4*((-c)^(1/2) - (d*x - c)^(1/2))^17) + (311*b*c^6*((c + d*x)^(1/2)
- c^(1/2))^19)/(4*((-c)^(1/2) - (d*x - c)^(1/2))^19) - (175*b*c^6*((c + d*x)^(1/2) - c^(1/2))^21)/(12*((-c)^(
1/2) - (d*x - c)^(1/2))^21) + (5*b*c^6*((c + d*x)^(1/2) - c^(1/2))^23)/(4*((-c)^(1/2) - (d*x - c)^(1/2))^23))/
(d^7 - (12*d^7*((c + d*x)^(1/2) - c^(1/2))^2)/((-c)^(1/2) - (d*x - c)^(1/2))^2 + (66*d^7*((c + d*x)^(1/2) - c^
(1/2))^4)/((-c)^(1/2) - (d*x - c)^(1/2))^4 - (220*d^7*((c + d*x)^(1/2) - c^(1/2))^6)/((-c)^(1/2) - (d*x - c)^(
1/2))^6 + (495*d^7*((c + d*x)^(1/2) - c^(1/2))^8)/((-c)^(1/2) - (d*x - c)^(1/2))^8 - (792*d^7*((c + d*x)^(1/2)
- c^(1/2))^10)/((-c)^(1/2) - (d*x - c)^(1/2))^10 + (924*d^7*((c + d*x)^(1/2) - c^(1/2))^12)/((-c)^(1/2) - (d*
x - c)^(1/2))^12 - (792*d^7*((c + d*x)^(1/2) - c^(1/2))^14)/((-c)^(1/2) - (d*x - c)^(1/2))^14 + (495*d^7*((c +
d*x)^(1/2) - c^(1/2))^16)/((-c)^(1/2) - (d*x - c)^(1/2))^16 - (220*d^7*((c + d*x)^(1/2) - c^(1/2))^18)/((-c)^
(1/2) - (d*x - c)^(1/2))^18 + (66*d^7*((c + d*x)^(1/2) - c^(1/2))^20)/((-c)^(1/2) - (d*x - c)^(1/2))^20 - (12*
d^7*((c + d*x)^(1/2) - c^(1/2))^22)/((-c)^(1/2) - (d*x - c)^(1/2))^22 + (d^7*((c + d*x)^(1/2) - c^(1/2))^24)/(
(-c)^(1/2) - (d*x - c)^(1/2))^24) - ((23*a*c^4*((c + d*x)^(1/2) - c^(1/2))^3)/(2*((-c)^(1/2) - (d*x - c)^(1/2)
)^3) - (3*a*c^4*((c + d*x)^(1/2) - c^(1/2)))/(2*((-c)^(1/2) - (d*x - c)^(1/2))) + (333*a*c^4*((c + d*x)^(1/2)
- c^(1/2))^5)/(2*((-c)^(1/2) - (d*x - c)^(1/2))^5) + (671*a*c^4*((c + d*x)^(1/2) - c^(1/2))^7)/(2*((-c)^(1/2)
- (d*x - c)^(1/2))^7) + (671*a*c^4*((c + d*x)^(1/2) - c^(1/2))^9)/(2*((-c)^(1/2) - (d*x - c)^(1/2))^9) + (333*
a*c^4*((c + d*x)^(1/2) - c^(1/2))^11)/(2*((-c)^(1/2) - (d*x - c)^(1/2))^11) + (23*a*c^4*((c + d*x)^(1/2) - c^(
1/2))^13)/(2*((-c)^(1/2) - (d*x - c)^(1/2))^13) - (3*a*c^4*((c + d*x)^(1/2) - c^(1/2))^15)/(2*((-c)^(1/2) - (d
*x - c)^(1/2))^15))/(d^5 - (8*d^5*((c + d*x)^(1/2) - c^(1/2))^2)/((-c)^(1/2) - (d*x - c)^(1/2))^2 + (28*d^5*((
c + d*x)^(1/2) - c^(1/2))^4)/((-c)^(1/2) - (d*x - c)^(1/2))^4 - (56*d^5*((c + d*x)^(1/2) - c^(1/2))^6)/((-c)^(
1/2) - (d*x - c)^(1/2))^6 + (70*d^5*((c + d*x)^(1/2) - c^(1/2))^8)/((-c)^(1/2) - (d*x - c)^(1/2))^8 - (56*d^5*
((c + d*x)^(1/2) - c^(1/2))^10)/((-c)^(1/2) - (d*x - c)^(1/2))^10 + (28*d^5*((c + d*x)^(1/2) - c^(1/2))^12)/((
-c)^(1/2) - (d*x - c)^(1/2))^12 - (8*d^5*((c + d*x)^(1/2) - c^(1/2))^14)/((-c)^(1/2) - (d*x - c)^(1/2))^14 + (
d^5*((c + d*x)^(1/2) - c^(1/2))^16)/((-c)^(1/2) - (d*x - c)^(1/2))^16) - (3*a*c^4*atanh(((c + d*x)^(1/2) - c^(
1/2))/((-c)^(1/2) - (d*x - c)^(1/2))))/(2*d^5) - (5*b*c^6*atanh(((c + d*x)^(1/2) - c^(1/2))/((-c)^(1/2) - (d*x
- c)^(1/2))))/(4*d^7)